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# Review 6
* Hajin Ju, 2024062806
## Problem 1
Illustrate the operation of `PARTITION` on the array $A = \set{2, 8, 7, 1, 3, 5, 6, 4}$
### Solution 1
```python {cmd output=html hide}
from __pyfunc__.r6 import *
from bs4 import BeautifulSoup
data = [2, 8, 7, 1, 3, 5, 6, 4]
hl = [0, 0, 0, 0, 0, 0, 1, 0]
print(
create_array_table(data,
[0, 0, 0, 0, 0, 0, 1, 0]
, 0, 0),
)
print(
create_array_table(data,
[1, 0, 0, 0, 0, 0, 1, 0],
1, 0)
)
print(
create_array_table(
[2, 8, 7, 1, 3, 5, 6, 4],
[1, 1, 0, 0, 0, 0, 1, 0],
1, 1)
)
print(create_array_table(
[2, 8, 7, 1, 3, 5, 6, 4],
[1, 0, 1, 0, 0, 0, 1, 0],
1, 2
))
print(create_array_table(
[2, 1, 7, 8, 3, 5, 6, 4],
[0, 1, 0, 1, 0, 0, 1, 0],
2, 2
))
print(create_array_table(
[2, 1, 3, 8, 7, 5, 6, 4],
[0, 0, 1, 0, 1, 0, 1, 0],
3, 2
))
print(create_array_table(
[2, 1, 3, 8, 7, 5, 6, 4],
[0, 0, 1, 0, 0, 1, 1, 0],
3, 3
))
print(create_array_table(
[2, 1, 3, 8, 7, 5, 6, 4],
[0, 0, 1, 0, 0, 0, 1, 0],
3, 4
))
print(create_array_table(
[2, 1, 3, 4, 7, 5, 6, 8],
[0, 0, 1, 1, 0, 0, 0, 1],
0, 0
))
```
## Problem 2
Answer questions about the following function `SELECT(A, p, r, i)` where $r-p + 1 = n$
```py
SELECT(A, p, r, i)
if p == r
return A[p]
q = PARTITION(A, p, r)
k = q - p + 1
if i == k
return A[q]
else if i < k
return SELECT(A, p, q - 1, i)
else
return SELECT(A, q + 1, r, i - k)
```
* What does it do?
* What is the worst-case running time?
* What is the best-case running time?
### Solution 2-a
`SELECT` selects `i`-th smallest element in the array `A`.
### Solution 2-b
The worst-case occurs when the `PARTITION` partitiend the array unbalanced.
So, time-complexity of the case is:
$$T(n) = T(n-1) + O(n)$$
$$\therefore T(n) = O(n^2)$$
### Solution 2-c
The best-case occurs when the `PARTITION` partitiend the array balanced, which means pivot is median.
So, time-complexity of the case is:
$$T(n) = T(0) + O(n)$$
$$\therefore T(n) = O(n)$$